Wolframul pur poate fi obţinut prin reducerea oxidului de Wolfram (VI) cu: a) Zinc; b)oxid de carbon (II); c) aluminiu; d) hidrogen.

Alcătuieşte ecuaţia reacţiei pentru una din variante, egaleaz-o prin metoda bilanţului electronic, indică oxidantul şi reducătorul.

E-r

B-ē:

b. is the answer hoped i        

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally