Use graphing software plot E cell vs. ln([Fe2+]/[Fe3+]) for the three cell measurements in part 4. Determine the equation of the best fit line. E cell (volts)ln([Fe2+]/[Fe3+])
0.319 0
0.248 2.3
0.411 -2.3
2) From the best fit line calculate the value of n for the overall reaction.
Ecell = -(RT/nF) lnQ + Eocell
where Y = E cell, m=slope = -RT/nF, x = lnQ, and b = y-int = Eo cell
3) Based on the intercept associated with the best fit line, calculate the standard reduction potential for the Fe2+/Fe3+ half cell. Remember that the Eocell obtained form the graph is for the entire cell where Eocell = ECu, ox+ EoFe(III),red and EoCu, ox = -0.34 V. Determine a percent error based on the cited Fe(III)/F(II) reduction potential of +0.77V

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Explanation:

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.