Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . Suppose 1.5 g of hydrochloric acid is mixed with 2.67 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to significant digits.

The maximum amount of water that can be produced is 0.74 g

Explanation:

To calculate the number of moles, we use the equation:

     .....(1)  

Putting values in equation 1, we get:

The chemical equation for the reaction is

By Stoichiometry of the reaction:

1 mole of HCl reacts with 1 mole of NaOH

So, 0.041 moles of HCl will react with = of NaOH

As, given amount of NaOH is more than the required amount. So, it is considered as an excess reagent. Thus, HCl is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of HCl produces = 1 mole of water

So, 0.041 moles of HCl will produce = of water

Mass of water=

Thus the maximum amount of water that can be produced is 0.74 g

the dependant variable is spilled water

the independent is the heat

i think   the answer is c hope i'm right