4. How many moles of NaOH(s) would be required to react with 1.90 g of Cu(NO3)2 (aq) according to the balanced equation:
Cu(NO3)2(aq) + 2 NaOH(aq) → Cu(OH)2(s) + 2 NaNO3(aq)

2.03 x 10⁻² mol NaOH

Explanation:

First step for these questions is to ensure the reaction is balanced, then use the periodic table to determine the molar mass for the reactant you are given. Use the ratio from the balanced equation and dimensional analysis to solve. See attached image

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

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