What final temperature will be attained by a 250. g sample of Cu at 20.0oC if it absorbs 1000 J of heat? Cu 's c = 0.39 J/(g oC

30.26 °C

Explanation:

From the question,

Q = cm(t₂-t₁) Equation 1

Where Q = Heat, c = specific heat capacity of Cu, m = mass of Cu, t₁ = Initial temperature, t₂ = Final temperature.

Given: Q = 1000 J, c = 0.39 J/g.°C, t₁ = 20°C, m = 250 g

Substitute into equation 1 and solve for t₂

1000 = 250×0.39(t₂-20)

250×0.39(t₂-20) = 1000

97.5(t₂-20) = 1000

(t₂-20) = 1000/97.6

(t₂-20) = 10.26

t₂ = 10.26+20

t₂ = 30.26 °C

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