Calculate the heat absorbed, in kJ, when 2000. g of water is heated from 20.0 °C to 99.7 °C in an electric kettle

666.93 kJ

Explanation:

Using the formula;

Q = m × c × ∆T

Where;

Q = amount of heat absorbed (Joules)

m = mass of substance (g)

c = specific heat capacity (4.184 J/g°C)

∆T = change in temperature (°C)

Based on the information provided in the question;

Q = ?

m = 2000g

∆T = 99.7 °C - 20 °C = 79.7 °C

c = 4.184 J/g°C

Using Q = m × c × ∆T

Q = 2000 × 4.184 × 79.7

Q = 666929.6 Joules

To calculate the amount of heat absorbed (Q) in kilojoules (kJ), we say;

1 joule = 0.001 kilojoule

666929.6 Joules = 666929.6 × 0.001

= 666.9296 KJ

Approximately, Q = 666.93 kJ.

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