You titrate 25.00 ml of 0.1894 M acetic acid with 0.2006 M NaOH. How many ml of NaOH (to four significant figures) will be required at the equivalence point?

23.60 mL NaOH

Explanation:

The reaction is CH3COOH + OH- --> CH3COO+ + H2O

Since the reaction is one-to-one, we can use M1V1 = M2V2.

M1 = 0.1894 M CH3COOH

V1 = 25.00 mL CH3COOH

M2 = 0.2006 M NaOH

V2 = ?

Solve for V2 --> V2 = M1V1/M2

V2 = (0.1894 M)(25.00 mL) / (0.2006 M) = 23.60 mL NaOH

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