UNIT: ENERGY, REACTION RATES, AND EQUILIBRIUM OF CHEMICAL REACTIONS UNIT NOTES . Click the links to open the resources below. These resources will help you complete the assignment. Once you have created your file(s) and are ready to upload your assignment, click the Add Files button below and select each file from your desktop or network folder. Upload each file separately.

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1. Drag the empty jar to the lake to get a water sample  

2. Fill two beakers with 600 ml water from the jar

3. Put the “1” and “2” labels on each beaker  

4. Take the pH meter to Beaker 1 and record the pH and description in Table A  

5. Take the pH meter to Beaker 2 and record the pH and description in Table B

6. Add 1 unit of each base (soap, alkaline batteries, baking soda) to Beaker 2 and record the pH and description in Table B and clear

7. Add 1 unit of each acid (lead acid batteries, pesticides, citric acid) to Beaker 2 and record the pH and description in Table B and clear  

8.  Add 3 units of each kind of base or acid (the “pollutants”) to Beaker 2 and record the pH and description in Table A.

9. Get a new beaker and label it with a “3” and put the filter on the beaker

10. Add the polluted water from Beaker 2 to the filter on Beaker 3 and record the pH and description in Table A

11. Drag the rain clouds from the tools to the lake model and observe what happens to the rainwater and groundwater and record observations on Table C

12. Drag a lake to the model and observe the effects on the groundwater and record your observations on Table C

13.  Add 10 units of each pollutant to the lake  

14. Observe the changes in the lake water and the groundwater and record your observation in Table C

Explanation:

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm