How many moles of aspirin (C9H8O4) are contained in 3.13 g of aspirin?

The correct answer is - 0.0173888 moles.

Explanation:

Aspirin,  C 9 H 8 O 4 , the atomic mass rounded to the nearest whole number, so: c- 12 h- 1 o - 16

now multiply these number by how many of each there are in the formula:

c - 12 x 9 = 108

h - 1 x 8 = 8

0 - 16 x 4 = 64

add these numbers up 108 + 8 + 64 = 180

aspirin has a molar mass of  

180.g mol ^− 1 . This means that one mole of aspirin will have a mass of 180 g .

You're dealing with 3.13 g  of aspirin, which will be equivalent to

3.13 g  /180g

=  0.0173888 moles aspirin

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