Write a detailed mechanism for the following reaction. Draw step one of the mechanism which forms the initial enolate. Draw only the enolate form of the reaction, NOT the carbanion. Include lone pairs and formal charges in the mechanism. Draw out explicitly only the ONE hydrogen that is removed in this mechanistic step. DO NOT USE ABBREVIATIONS SUCH AS OEt for OCH2CH3.

the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products

b) nuclear ive learned that in a pedtrodic table

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.