How many moles of NaOH are contained in 56.0 mL of a 2.40 M solution of 1 point NaOH in water? (**Use only numerical answers with 3 significant figures.
The units are given in the question.)
Your answer

1.34 mol

Explanation:

Molarity, which is the molar concentration of a solution, can be calculated by dividing the number of moles (n) by the volume (V).

That is;

Molarity (M) = n/V

According to the information provided in this question;

M = 2.40M

V = 56.0 mL = 56/1000 = 0.056 L

Since molarity = n/V

number of moles = M × V

n = 0.056 × 24

n = 1.34 mol

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