2NH3 + MgSO4 +2H2O β> Mg(OH)2 + (NH4)2SO4
Using the chemical equation above answer the following questions.
1) If I have 4.2 moles of MgSO4 and 5.4 moles of NH3 which one is the limiting reactant?
2) What is the greatest amount of Mg(OH)2 that can be made with 4.6 moles of MgSO4 and 5.4 moles of NH3?
3) How many moles of the excess reactant is left over after the reaction has been completed?
Answers: 2
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2NH3 + MgSO4 +2H2O β> Mg(OH)2 + (NH4)2SO4
Using the chemical equation above answer the following...
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