1) In a process facility, you have two liquid streams with only methanol and water coming in from two separate processes. Stream 1 contains 80% of methanol by moles and Stream 2 contains 30% of methanol by moles. Your manager says you need to mix these together and flash it in a column. The temperature of operation is 400 K and you need to operate at a pressure that is nearly the average of the vapor pressures of methanol and water at 400 K. The VLE plot for methanol and water at 400 K is given to you (see below). (a) What is the vapor pressure of methanol and water? What is the operating pressure? You can round off the operating pressure to the nearest integer for further calculations (1.5 points) (b) What will be the composition of liquid and vapor product if you flash Stream 1 and Stream 2 individually (without mixing) at the operating pressure and temperature? (2 points) (c) Your manager now tells you that he needs half of the net product as a vapor. What ratio of streams 1 and 2 should you mix and flash at given operating pressure and temperature so as to get the desired product? (7 points) (d) Now you take the product vapor and liquid from (c), mix it and pass it through another flash drum operating at 400 K and 65 atm pressure. What is the composition (mole fractions) of your final liquid and vapor product? Approximate values are acceptable (1.5 points)

  remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.

Ibelieve the answer is d. titaniumhope my answer has you : )

Answerionic bond imfs are stronger than covalent;