If 35.4 liters of hydrogen gas are used, how many liters of nitrogen gas will be needed for the above reaction at stp ​

11.8 L

Explanation:

Step 1: Write the balanced reaction between hydrogen and nitrogen

3 H₂(g) + N₂(g) = 2 NH₃(g)

Step 2: Calculate the moles corresponding to 35.4 L of H₂

At STP, 1 mole of H₂ occupies 22.4 L.

35.4 L × 1 mol/22.4 L = 1.58 mol

Step 3: Calculate the moles of N₂ required to react with 1.58 moles of H₂

The molar ratio of H₂ to N₂ is 3:1. The moles of N₂ required are 1/3 × 1.58 mol = 0.527 mol

Step 4: Calculate the volume occupied by 0.527 moles of N₂ at STP

At STP, 1 mole of N₂ occupies 22.4 L.

0.527 mol × 22.4 L/1 mol = 11.8 L