Food Energy Math For this assignment you will have to calculate the food energy required to power various devices. You will be required to select 5 foods you have at your home and calculate how many of each item will be required to perform each mechanical or electrical process. Remember to calculate the per item calories; a serving of 2 chocolate sandwich cookies is 80 calories, one sandwich cookie is 40 calories.
For example, a coffee maker will require about 400 Watts of energy to run for an hour. 1 Kilocalorie is equal to 1.163 Watts, so the coffeemaker will require 343.9 Kilocalories to run for this length of time. If it could be converted to electricity how many fastfood cheeseburgers, (417 calories) would that require? Only 1 cheeseburger
Conversions:
1 Kcal- 1.163 Watts per hour
31,500 Kcal – 1 Gallon of gasoline

https://courses.lumenlearning.com/cheminter/chapter/energy-in-food-and-nutrition/

Explanation:

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole