How many liters of nitrogen gas (N₂) are required to produce 7.5 x 10²⁶ molec NH₃ gas with excess of hydrogen gas at STP?

The volume of nitrogen gas that is required is 13944 L.

Explanation:

Given values:

Number of molecules of ammonia gas =

According to the mole concept:

number of molecules are present in 1 mole of a compound

So, number of molecules will be present in of ammonia gas

The chemical equation for the formation of ammonia gas follows:

According to the stoichiometry of the reaction:

2 moles of ammonia gas are produced from 1 mole of nitrogen gas

So, moles of ammonia gas will be produced from moles of nitrogen gas

At STP conditions:

1 mole of a gas occupies 22.4 L of volume

So, moles of nitrogen gas will occupy of volume

Hence, the volume of nitrogen gas that is required is 13944 L.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)