A gas sample has a volume of 185 mL at 45°C. What is its volume at 109°C?

121

Explanation:

342 mL

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 185 mL

Initial temperature (T₁) = 45 °C

Final temperature (T₂) = 109 °C

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 45 °C

Initial temperature (T₁) = 45 °C + 273

Initial temperature (T₁) = 318 K

Final temperature (T₂) = 109 °C

Final temperature (T₂) = 109 °C + 273

Final temperature (T₂) = 382 K

Finally, we shall determine the final volume of the gas as follow:

Initial volume (V₁) = 185 mL

Initial temperature (T₁) = 318 K

Final temperature (T₂) = 382 K

Final volume (V₂) =?

V₁/T₁ = V₂/T₂

285 / 318 = V₂ / 382

Cross multiply

318 × V₂ = 285 × 382

318 × V₂ = 108870

Divide both side by 318

V₂ = 108870 / 318

V₂ ≈ 342 mL

Therefore, the new volume of the gas is 342 mL

342 mL

Explanation:

Hope this helps

the answer is true.