Consider the following chemistry equation: 2C2H6 + 7O2 --> 6H2O + 4CO2 How many grams of water can be produced from 13.5 grams of C2H6?

24.3 grams H2O
2.70 grams H2O
67.5 grams H2O
47.1 grams H2O

Consider the following chemical reaction:
H2 + O2 --> H2O
How many liters of oxygen gas is needed to produce 2.73 liters of water vapor?
22.4 liters O2
30.6 liters O2
5.46 liters O2
1.37 liters O2

i belive it is water

answer is: empirical formula is tl₂o. if we use 100 grams of compound, tha:

m(tl) = 96.2%  · 100 g ÷ 100%.

m(tl) = 96.2 g.

n(tl) = m(tl)  ÷ m(tl). n(tl) = 96.2 g  ÷ 204.4 g/mol.

n(tl) = 0.47 mol. m(o) = 3.77 g. n(o) = m(o)  ÷ m(o). n(o) = 3.77 g  ÷ 16 g/mol. n(ag) = 0.235 mol. n(tl) . n(o) = 0.47 mol : 0.235 mol /0.235. n(tl) . n(o) = 2 : 1.

m(tl₂o) = 204.4 g/mol  · 2 + 16 g/mol = 424.8 g/mol.

m(compound) = 456. 8 g/mol - 424.8 g/mol = 32 g/mol ( 2 oxygens); tl₂o₃.