How many grams of Ag2S are produced from 10.0
grams of AgI?
10
AgI + Nazs
Ag2S +NaI

10.0 g of AgI will produce 5.28 g of Ag₂S

Explanation:

The balanced equation of the reaction is given below:

2AgI + Na₂S > Ag₂S + 2NaI

From the equation of reaction, 2 moles of AgI produces 1 mole of Ag₂S

The moles of a substance is related to its mass by a quantity known as molar mass which is defined as the mass of one mole of that substance.

Molar mass of AgI = (108 + 127) g = 235 g

Molar mass of Ag₂S = (108 × 2 + 32) g= 248 g

Mass of 2 moles of AgI = 2 × 235 g = 470 g

470 g of AgI produces 248 g of Ag₂S

10 g of AgI will produce 248 /470 × 10 g of Ag₂S = 5.28 g

Therefore, mass of Ag₂S produced = 5.28 g