The pressure in a tire is 101 kPa at 10.0°C, what will be the pressure of a tire at 45.0°C?

P₂ = 113.49 kPa

Explanation:

Given that,

Initial pressure, P₁ = 101 kPa

Initial temperature, T₁ = 10.0°C = 283 K

Final temperature, T₂ = 45°C = 318 K

The relation between pressure and temperature is given by :

Where

P₂ is the new pressure

So,

So, the new pressure is equal to 113.49 kPa.

the answer is b. dilution