Can someone help me with the rest of the questions pls

2. About 138 g of KI will dissolve in 100 g of water at 10°C

3. 34.5 g of KI will dissolve in 25 g of water

4. The solution is not saturated but is unsaturated

Explanation:

From the graph:

1. KI is more soluble than KCl at 10°C because approximately 138g of KI dissolves at 10°C compared to 30 g of KCl per 100 g of water

2. About 138 g of KI will dissolve in 100 g of water at 10°C

3. 138 g of KI dissolves in 100 g of water at 10°C

In 25 g of water which is 1/4 × 100 g of water, 138/4 g = 34.5 g of KI will dissolve

Therefore, 34.5 g of KI will dissolve in 25 g of water

4.At 20 °C, a saturated solution of NaNO₃ will contain about 88 g of NaNO₃ in 100 g of water.

The solution prepared by the chemist contains 45 g of NaNO₃ in 100 g of water at 20 °C. The amount of solute present in the solution is less thanthe solvent can dissolve at that temperature, therefore, the solution is not saturated.

thats how its supposed to be