A gas has a volume of 590 mL at a temperature of –55.0°C. What The temperature be if the volume expands to 15L at constant pressure?

5542.37 K

Explanation:

Given that,

Initial volume, V₁ = 590 mL

Initial temperature, T₁ = -55°C = -55 + 273 = 218 K

Final volume, V₂ = 15 L

We need to find the final temperature of the gas. The relation between the volume and the temperature is given by :

Where

T₂ is final volume of the gas

Put all the values in above relation,

So, the required temperature is equal to 5542.37 K.

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.