Sulfuric acid (H2SO4) and Ba(OH)2 solutions are strong electrolytes and give a bright glow on the light bulb of your conductivity apparatus. When Ba(OH)2 is added dropwise to H2SO4, a precipitate is formed and the light bulb of the conductivity apparatus dims and eventually fades completely. Required:
a. Briefly explain this phenomenon.
b. Write the balanced equation of the reaction between these solutions.

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explanation:

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c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.

pv=nrt

explanation: