Whats is tge electron configuration of Ag2+ please answer asap..

1s2  2s2  2p6  3s2  3p6  3d10 4s2  4p6  4d10

Explanation:

To write the configuration for the Silver and the Silver ion, first we need to write the electron configuration for just Silver (Ag).  We first need to find the number of electrons for the Ag atom (there are 47 electrons) using the Periodic Table.   When we write the configuration, we'll put all 47

Either way,  the Silver  electron configuration will be 1s2  2s2  2p6  3s2  3p6  3d10 4s2  4p6  4d10  5s1    

Note that when writing the electron configuration for an atom like Ag and Ag+, the 4d is usually written before the 5s.   Both of the configurations have the correct numbers of electrons in each orbital, it is just a matter of how the electronic configuration notation is written (see below for an explanation why).

For the Ag+, called the Silver ion,  we remove one electron from 5s2 leaving us with:

1s2  2s2  2p6  3s2  3p6  3d10 4s2  4p6  4d10

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

i'm pretty sure its b i might be wrong though!