Propane(C_3H_8 Delta H_f = -104.63 kJ/mol) reacts with oxygen to produce carbon dioxide (CO_2 Delta H_f = -393.5 kJ/mol) and water (H_2O DeltaH_f = -241.82 kJ/mol) According to the equation Down below C_3H_8 + 3O_2 -> 3CO_2 + 4H_2O.

Why is the Enthalpy of Combustion of C_3H_8 in the reaction that I showed above?

Any help would be greatly appreciated. (also if you could help show how you did it that would be nice)

(And please for the love of god dont say any $h!t like "all i know about this question is that combustion involves burning/heat"

or "Here is a link to this scam download virus thing"

that is not really an answer.

i just want help with this one thing and I dont really use points so i am putting 100 points on this)