Determine the hydronium ion concentration Big Points in a solution that is 0.00013 M HCl.

Answer in units of M.

040 (part 2 of 2) 10.0 points

Determine the hydroxide ion concentration in

a solution that is 0.00013 M HCl.

Answer in units of M.

[H⁺] = 0.00013 M

[OH⁻] = 7.7 × 10⁻¹¹ M

Explanation:

Step 1: Calculate the concentration of H⁺ ions

HCl is a strong acid that dissociates according to the following equation.

HCl ⇒ H⁺ + Cl⁻

The molar ratio of HCl to H⁺ is 1:1. The concentration of H⁺ is 1/1 × 0.00013 M = 0.00013 M.

Step 2: Calculate the concentration of OH⁻ ions

We will use the ionic product of water equation.

Kw = 10⁻¹⁴ = [H⁺] × [OH⁻]

[OH⁻] = 10⁻¹⁴/[H⁺] = 10⁻¹⁴/0.00013 = 7.7 × 10⁻¹¹ M

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%