NEED HELP ASAP A concept map for four types of intermolecular forces and a certain type of bond is shown.

Compare the relative strength of the two forces B and C. Explain how you determined this comparison by identifying the forces.

A= Covalent bonding.

B = Dispersion forces.

Explanation:

This particular question wants to test our knowledge on chemical attractions in molecules. Kindly check the picture attached to get a glimpse of the two forces being compared here.

The force of attraction in B is known as the Dispersion forces. It is the kind of forces of attraction that happens when hydrogen bonds do not happen. Literarily, when Hydrogen  atoms reacts with more electronegative atoms such as oxygen, Fluorine and Nitrogen, the kind of bond that will be formed will be an hydrogen bond. So, if hydrogen bond is not formed, then a weaker bond will be formed which is the Dispersion forces of attraction. Hence, B is the Dispersion forces.

Covalent bonds are the kind of bonds that involves that atoms shares electrons in order for chemical bonding to occur. Although, there is H2O which is a polar covalent bond. There are other compounds that are not polar such as CS2 and CH4. Therefore, the kind of attraction in A is covalent bonding.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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