PLEASE HELP ME AND MAKE SURE TO SHOW YOUR WORK!! Ozone (O₃) in the atmosphere may react with nitric oxide (NO). O₃(g)+NO(g)→NO₂(g)+O₂(g)
From the following data calculate DG° in kJ for the reaction at 25°C and determine whether the reaction is spontaneous.
ΔH°=-199kJ ΔS°=-4.1J/K

ΔG°  = 1022. 8 kJ

ΔH° = –199 kJ/mol

ΔS° = –4.1 J/K·mol

T = 25°C = 25 + 273 = 298K (Converting to kelvin temperature)

ΔG° = ?

Explanation:The relationship between these varriables are;

ΔG° = ΔH°  - TΔS°

ΔG° = –199 - 298 (–4.1)

ΔG° = -199 + 1221.8

ΔG°  = 1022. 8 kJ

sorry if uncorrect

3 hours because it is a decent distance.