How many grams of AgCl are produced from 10.0 g AgNO3?

Equation of Reaction = AgNO3 (aq) + NaCl (aq) → AgCl (s) + NaNO3 (aq)

Steps:

1. Find the moles of AgNO3 with formula n= Mass/Mr (molecular mass)

so you will get moles= 10.0/ 169.87 = 0.05886854654

2. Using stoichiometry you know the equation has 1 mole so the moles of AgCl are gonna be the same; therefore, you will use again the same formula.

3.  moles= mass/molecular mass

0.05886854654 = x/ 143.32

You rearrange the formula to find the mass

so mass = moles x molecular mass

mass = 0.05886854654 x 143.32

mass= 8.44 grams

Explanation:

under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?

answer///carbon;