If it takes 75.0 mL of 1.5 M HNO3 solution to completely neutralize 125 mL of Ca(OH)2, what is the concentration of the Ca(OH)2 solution?

0.45 M

Explanation:

The reaction that takes place is:

First we calculate how many HNO₃ moles reacted, using the given concentration and volume:

Then we convert HNO₃ moles into Ca(OH)₂ moles, using the stoichiometric coefficients:

Finally we calculate the concentration of the Ca(OH)₂ solution:

i think its 5049.

i hope this !