29g of copper pellets are removed from a 300 celsius oven and immediately dropped into 100 ml of water at 22 celcius in an insulated cup.

what will the new water temperature be?

If we use the next formula to determine this:ΔQ=mcΔT
Then we can get to the result. Because of the conservation of energy, the quantity of heat remains the same. So what we do is:c1∗m1∗(T1−T∗)=c2∗m2∗(T∗−T2) when plugging in 0.39 for copper and 4.19 we get 29°C for the resulting temperature. I hope this can help you