X Question 16
4 Points
A 350. mL solution of 0.150 M HNO 3(aq) is mixed with a solution of 230. mL of 0.240 M HCl(aq). How many moles of H (aq)
are present in the final solution?
А
0.0525 moles H+
(B) 0.108 moles H+
C) 0.195 moles H+
D) 0.0539 moles H+
E 0.186 moles H*

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles