A tank of gas is found to exert 8.6 atm at 38°C. What would be the required temperature to change the pressure to standard pressure?

36.2 K

Explanation:

Step 1: Given data

Step 2: Convert T₁ to Kelvin

We will use the following expression.

K = °C +273.15

K = 38 °C +273.15 = 311 K

Step 3: Calculate T₂

We will use Gay Lussac's law.

P₁/T₁ = P₂/T₂

T₂ = P₂ × T₁/P₁

T₂ = 1.0 atm × 311 K/8.6 atm = 36.2 K

14 days is the half-life of phosphorus-32

i think its 100

i hope this !