1.) Calculate the molarity of a solution prepared by dissolving 6.434 g of KCl in water to make a 1.500 L solution. 2.) If 10.0 g of silver nitrate is available, what volume of 0.25 M silver nitrate can be prepared?

3.) A laboratory procedure calls for a 0.250 M solution of cobalt (II) chloride. How many grams of cobalt (II) chloride are needed to make 0.500 L of this solution?

4.) 14.4 g of magnesium nitrate is dissolved in 1.20 L of water. 25 mL of this solution is taken and diluted to 175 mL with water. What is the final concentration of the nitrate ion?

(a)The molarity of KCl solution is, 0.9713 mole/L

(b)The molarity of  solution is, 0.00525 mole/L

(c)The molarity of  solution is, 0.0612 mole/L

(d)The molarity of  solution is, 7.61 mole/L

(e)The molarity of  solution is, 0.0565 mole/L

(f)The molarity of  solution is, 0.0113 mole/L

Explanation :

(a) 1.457 mol of KCl in 1.500 L of solution

Formula used :

Solute is KCl.

The molarity of KCl solution is, 0.9713 mole/L

(b) 0.515 gram of , in 1.00 L of solution

Formula used :

Solute is

Molar mass of  = 98 g/mole

The molarity of  solution is, 0.00525 mole/L

(c) 20.54 g of  in 1575 mL of solution

Formula used :

Solute is

Molar mass of  = 213 g/mole

The molarity of  solution is, 0.0612 mole/L

(d) 2.76 kg of  in 1.45 L of solution

Formula used :

Solute is

Molar mass of  = 250 g/mole

The molarity of  solution is, 7.61 mole/L

(e) 0.005653 mol of  in 10.00 ml of solution

Formula used :

Solute is .

The molarity of  solution is, 0.0565 mole/L

(f) 0.000889 g of glycine, , in 1.05 mL of solution

Formula used :

Solute is

Molar mass of  = 75 g/mole

The molarity of  solution is, 0.0113 mole/L

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.