If 20.0 g NaOH reacts with 30.0 g of H2SO4 how much Na2SO4 is produced? Given: 2NaOH(aq) + H2SO4(aq) | Na2SO4(aq) + 2H2O(l)

10g

Explanation:

find the limiting agent first

using mole ratio

2 moles of NAOH reacts with 2 moles of H2SO4

then 20g of NAOH require 20g of H2SO4

USING mole ratio on the limiting agent and product

2moles of NAOH produces 1 mole of NA2SO4

THEN

20g of NAOH will produce X

THEN solve for X

X =10g

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer