How many moles of nitrogen gas will be produced by the rapid decomposition of 140 g of azide NaN3 in the reaction? 2NaN3 ⟶2Na +3N2

Given: Formula weight for Na= 23 g/mol, Formula weight N=14 g/mol,

Group of answer choices

1.44 mol

2.12 mol

42 mole

3.23 mol

Flag question: Question 2
Question 22.5 pts
What volume of nitrogen gas do you expect to be produced by the azide decomposition? (Hint: 1 mole of ANY gas occupies 22.4 L at STP)

2NaN3 ⟶2Na +3N2

Given: Formula weight for Na= 23 g/mol, Formula weight N=14 g/mol

Group of answer choices

37.1L

48.2 L

72.4 L

32.3 L

Flag question: Question 3
Question 32.5 pts
How many grams of sodium metal will be produced from 140g of NaN3?

2NaN3 ⟶2Na +3N2

Given: Formula weight for Na= 23 g/mol, Formula weight N=14 g/mol

Group of answer choices

42.0 g

49.5 g

99.0 g

2.15 g

Flag question: Question 4
Question 42.5 pts
How many grams of sodium azide are required to produce 275g of N2?

2NaN3 ⟶2Na +3N2

Given: Formula weight for Na= 23 g/mol, Formula weight N=14 g/mol

Group of answer choices

856 g

957 g

426 g

15 g