if 0.200 moles of AgNO3 react with 0.155 moles of H2SO4 according to this UNBALANCED equation below, how many grams of AgSO4 could be formed? AgNO3+H2SO4->Ag2SO4+HNO3

62.36 g

Explanation:

AgNO3 + H2SO4 - > Ag2SO4   + HNO3

The balanced equation is given as;

2AgNO3 + H2SO4 → Ag2SO4 + 2HNO3  

From the equation;

2 mol of AgNO3 reacts with 1 mol of H2SO4

if 0.200 moles of AgNO3 react with 0.155 moles of H2SO4

The limiting reactant us AgNO3 as it determines the amount of products to be formed.

2 mol of AgNO3 produces 1 mol of Ag2SO4

0.2 mol of AgNO3 would produce x mol of Ag2SO4

Solving for x;

2 = 2

0.2 = x

x =0.2 * 2/ 2 = 0.2 mol

Converting moles to mass;

Mass = Number of Moles * Molar mass

Mass = 0.2 mol * 311.8 g/mol

Mass = 62.36 g

i think so it’s will be b yes i believe its

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