A 126-gram sample of titanium metal is heated from 20.0°C to 45.4°C while absorbing 1.68 kJ of heat. What is the specific
heat of titanium?

The specific heat for the titanium metal is 0.524 J/g°C. Here, ΔT = T₂ - T₁ = 45.4 - 20 = 25.4°C.
Explanation:
Given,
Q = 1.68 kJ = 1680 Joules
mass = 126 grams
T₁ = 20°C
T₂ = 45.4°C
The specific heat for the metal can be calculated by using the formula
Q = (mass) (ΔT) (Cp)
Here, ΔT = T₂ - T₁ = 45.4 - 20 = 25.4°C.
Substituting values,
1680 = (126)(25.4)(Cp)
By solving,
Cp = 0.524 J/g°C.
The specific heat for the titanium metal is 0.524 J/g°C.

The answer is 65.3312