Chem practice test help

answer of I(matching place the letter)

1-I

2-E

3-B

4-A

5-J

6-C

7-G

8-H

9-F

10-D

Answer of II (PROBLEMS)

1. P1+P2+P3=10 atm

P3=10-3.5-5.5 =1 atm

2. 760mmHg= 1 atm

750mmHg= 1x750/760=0.98atm

3. V1/T1=V2/T2

PUT THE VALUES(TEMP MUST BE IN KELVIN)

5/22+273=V2/4+273

V2=5/295 X 277 = 4.69L

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

idk what is it? is this a question that you know the answer or u dont