This is the equation for the combustion of carbon monoxide is: CO + O2 CO2
How many liters of oxygen are needed to burn 2.76 L of carbon monoxide?

1,38 litres

Explanation: it should be 2 CO + O2 ⇒ 2 CO2

In Same temperature volumes are proportional

To amounts of substances. So amount of Oxygen is half of

Amount of CO

1.38 L O2

Explanation:

2CO + O2 = 2CO2

So,

1 mole CO = 22.4 L CO

2 mole CO = (22.4 ×‌‍‍2)L CO

= 44.8 L CO

And 1 mole O2 = 22.4 L O2

44.8LCO are burned by 22.4LO2 1 L CO are burned by 22.4÷ 44.8

= 0.5 L O2

2.76L CO are burned by0.5×2.76

= 1.38 L O2

So, 1.38 L O2 are needed to burn

2.76 L CO

i think slash and

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >