Calculate the change in heat (Q) that occurs when 54.31grams of liquid water at 147°C heats to water vapor at 438°C. (cp = 4.184 J/g°C)

66124.8 J

Explanation:

Using the formula;

Q = m × cp × ∆T

Where;

Q = change in heat (J)

m = mass of substance (g)

cp = specific heat capacity (4.184 J/g°C)

∆T = change in temperature (°C)

According to this question,

Q = ?

m = 54.31 grams

∆T (final - initial temperature) = 438°C - 147°C = 291°C

cp = 4.184 J/g°C

HENCE,

Q = m × cp × ∆T

Q = 54.31 × 4.184 × 291

Q = 66124.8 J

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