How many grams of Silver Nitrate must be added to the solution to completely react with Sodium Chloride according to the reaction below: NaCl(aq) + AgNO3(aq) → NaNO3(aq) + AgCl(s)

5.81g of AgNO₃ must be added

Explanation:

The solution contains 2.00g of sodium chloride.

Based on the reaction, 1 mole of NaCl reacts per mole of AgNO₃. To solve this question, we need to find the moles of NaCl in 2.00g and, these moles = Moles of AgNO₃ that must be added:

moles NaCl = Moles AgNO₃-Molar mass: 58.44g/mol:

2.00g * (1mol / 58.44g) = 0.0342 moles NaCl = Moles AgNO₃

Mass AgNO₃ -Molar mass: 169.87g/mol-:

0.0342 moles * (169.87g / mol) =

i think its 100

i hope this !

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