A solution was made by dissolving 3.75 g of a pure non-volatile solute in 95 g of acetone. The boiling point of pure acetone was observed to be 55.95°C, and that
of the solution was 56.50°C. If the molar boiling point elevation constant (Kb) of
acetone is 1.71°C kg/mol, what is the approximate molar mass of the solute?

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm