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Chemistry, 18.03.2021 09:40 hailee24

2 HCl (9) =H2(g) + Cl2 (9)
K = [H][CI]/[HCI)
UK = [H][CI]/2[HCI]
K = 2[HC]/[H]CI.)
K = [HCI)?/[H][1]

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2 HCl (9) =H2(g) + Cl2 (9)
K = [H][CI]/[HCI)
UK = [H][CI]/2[HCI]
K = 2[HC]/[H]CI....
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