A 200.0 ml quantity of 0.9 M HCl was titrated with an NaOH solution to reach the equivalence point. The goal was to determine the concentration of the NaOH solution. if 23.9 ml if the NaOH solution was required, what was the [NaOH]???

Since the acid and base react in a one to one ratio, you can use the equation M1V1 = M2V2 to solve for M2, or the molarity of NaOH.

M1 = 0.9 M HCl

V1 = 200.0 mL HCl

M2 = ?

V2 = 23.9 mL NaOH

(0.9 M)(200.0 mL) = M2(23.9 mL) —> M2 = 7.53 M NaOH

the ratio of the conjugate base to the acid required to attain the desired ph.

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.