Graphing Data Analysis Use your Graphing Practice assignment in Kami to answer the questions below.
Graph A Questions
1. Which month had the highest number of deer spotted?
2. Which month had the lowest number of deer spotted?
3. What happens to the number of deer seen from the month of September
to the month of February?
4. Why might this trend be occurring?
Graph B Questions
1. What is the trend of the line in this graph? (increasing, decreasing,
remaining the same)
2. What is the approximate number of bacteria that would exist in 3.5 days?
3. What do you predict would happen to the number of bacteria on day 7?
Graph C Questions
1. What is the relationship between hours of study and the grade received
2. What grade did this person get after studying for 8 hours
3. What would you expect the grade results to be after one hour of study

Iwould you figure it out but you don't have a picture or in your question as to what the physical property you're looking for is

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.