What is the volume of 340g of gaseous ammonia NH3 under standard conditions. (Vm = 22.41l).​

V(NH₃(g)) at STP = 0.8928 Liters ≅ 0.9 Liter (1 sig. fig)

Explanation:

Given 340g NH₃(g) => ?Volume at STP

Convert grams to moles by dividing by formula wt of ammonia

= 340g/17g/mole = 20 moles

1 mole of any gas at STP conditions (0°C, 1atm) occupies 22.41 Liters

∴ 20 moles NH₃(g) => 20moles/22.4Liters/mole

= 0.8928 Liters ≅ 0.9 Liter (1 sig. fig)

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