Give the hybridization for the C in HCN

Explanation:

In HCN,

Carbon is singly - bonded ( 1 sigma bond ) to Hydrogen while triply - bonded ( 1 sigma, 2 pi bonds) to Nitrogen.

Thus, the Stearic No. for Carbons is:

= No. of sigma bonds + No. of lone pairs

= 2 + 0

= 2

According to Stearic No.:

=> sp = 2

=> sp² = 3

=> sp³ = 4

Hence,

The hybridization of C in HCN is sp.

Hope this helped!

personal, she chose to do it.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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