What is the concentration of silver ions where silver iodide, Agl, is in a solution of hydroiodic acid, HI, that has a pH of 3.55? Ksp = 8.51x10-17

Explanation:

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In this case, for the ionization of silver iodide we have:

Now, since we have the effect of iodide ions from the HI, it is possible to compute that concentration as that of the hydrogen ions equals that of the iodide ones:

Now, we can set up the equilibrium expression as shown below:

Thus, by solving for x which stands for the concentration of both silver and iodide ions at equilibrium, we have:

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4d^55s^1 ( third choice)