A balloon has a volume of 105 Lif the temperature is 20 °C. If the temperature is -55°C, what will be the volume of the volume?

78.12 L

Explanation:

Given that,

Initial volume, V₁ = 105 L

Initial temperature, T₁ = 20°C = 20+273 = 293 K

New temperature, T₂ = -55 °C = 218 K

We need to find the new volume of the balloon. The relation between the volume and the temperature is given by :

Where

V₂ is the new volume

So, the new volume is 78.12 L.

d.) circle motion requires a force to give it a centripetal acceleration.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"